[填空题]
A force of 10.0 ± 0.2 N is applied.nlbcpr u,8yn53lt l 3 to a mass of 2.05bwjzvu8 :3ipg2 db*pcd 7 fm/ ± 0.01 kg, causing it to accelerate. What is the percentage uncgdfc/u db5mb:p*jv 8i2 w3zp7 ertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the*5lua8 vh6kxe;y8op 9ycogk * formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.