[填空题]
The potential differetj(2:g:otq w i +hs,vbcb (5ltnvt/6s. whf*y lce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital devic8lnm1a: y8lismy/7 cw2t 5 5f7vsznlde and so the uncertainty is the smallest value which it can 5m5lzfn1m8dtll : 72 ac/v yyn7wiss8 record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.