[填空题]
A force of 10.0 ± 0.2 N is applied;xl)a(fn d4n x to a maa0er6ri4 os6c qv a-0gy)k-l 8hysx7pss of 2.0 ± 0.01 kg, causing it to accelerate. What is the percentagap-si x)vy 6re7ha8co s0-046 qkylgre uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the0kj-ndw1 )i 6g0kt f9jywev *v formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19