[填空题]
The potential differ 9f:6dg;eu)n4t -fbbf+ vcwuk/1oa/ w(vsdf8r vzh6j0 qhtb1 ence ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty i i63 ,zfux 4h.wmfygksz53 oemgnw064s the smallest value which it cmou5fng6f zwiw .4,zs4 60k3hx3ymegan record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.
Post time 2024-8-21 21:38:19