[填空题]
The density of a solid sp-ig1 ne h lh(m1j,:wudhere is measured with percentage uncertarncev90d 5/1 k2va szdinty of 5%. The radius of the sphere is 4.0 svr 0za/cd92kde5v1n ± 0.2 cm. What is the percentage uncertainty in the mass of the sphere? % (Please do not include the % simbol in the blank)
参考答案: 20.0
本题详细解析: The mass of the sphere can be calculated by multiplying its volujl -t- w3 -jawgyk 2o2p6zglt;me by the density;t 6j gz l-ktapo--j 2w3wl2gy of the material of which it is made: $$M=\frac{4}{3} \pi r^3 \rho$$ so the percentage uncertainty in $M$ is $$\frac{\Delta M}{M}=3 \frac{\Delta r}{r}+\frac{\Delta \rho}{\rho} .$$ The percentage uncertainty in $r$ is $5 \%$, so the percentage error in $M$ is $(3 \times 5 \%)+5 \%=20 \%$
Post time 2024-8-21 21:38:19