[填空题]
A force of 10.0 ± 0.2 N isw3l(euk: u8v9oi ek4oy;tyil;0nx (j applied to a mr54 3 1 vmrn,xi8ptifnass of 2.0 ± 0.01 kg, causing it to accelerate. What is the percentage uncertr4r p3 n1, vnx8mitif5ainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using tuk hb+)u7u .:otkgsj4he formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19