[填空题]
A force of 10.0 ± 0.2 N94 yzmpev :vgr+fp85v5khmq , is applied to a ma4h;nx*t kk5hs ng u3k3scw1.fss of 2.0 ± 0.01 kg, causing it to accele41xswfk *ht.kku 35n hsnc;3 grate. What is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated h;zt* -eb iy2 ;ef(wyjusing the formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19